[support] Passing multiple values into a single Views argument

Wed Nov 24 19:03:27 UTC 2010

It's not a sql query. db_fetch_object is like mysql_fetch_object(). It's 
just grabbing a row from a result resource, which is what you get from 
db_query($sql, ...), which you (hopefully) run only once.

On 11/24/2010 01:50 PM, Neil Coghlan wrote:
> Ursula/Christopher,
>
> Thanks for this help. I'll try it later when I'm at home. The only thing
> that concerns me is that views was showing 5000ms for that view to
> render so I suspect having such a complicated nested sql query in there
> just to supply the arg is going to be a killer.
>
> Neil
>
> On 24/11/2010 15:42, Christopher M. Jones wrote:
>> Or, to avoid a stray '+' at the end,
>>
>> $members = array();
>> while( $member = db_fetch_object($result) ){
>>      $members[] = $member->uid;
>> }
>>
>> return implode('+', $members);
>>
>> On 11/24/2010 01:29 PM, Ursula Pieper wrote:
>>> Neil,
>>>
>>> If you use return inside the while loop like you do it, the loop will
>>> process the first return of the query (37), and return that value to
>>> the parent function. It basically will break the loop and won't go
>>> through it until the further entries are processed.
>>>
>>> You need to concatenate the fetched values to a variable (for
>>> example), and return that variable once the loop is finished.
>>> while($member = db_fetch_object($result)){
>>>        $variable.= $member->uid . "+";
>>> }
>>> return $variable;
>>>
>>> If you want to retrieve the values from the database ordered, you need
>>> to add an "order by node.uid asc" to the SQL query.
>>>
>>> Hope this helps, Ursula
>>>
>>> On Tue, Nov 23, 2010 at 7:10 AM, Neil Coghlan<neil at esl-lounge.com>    wrote:
>>>> this is where I'm up to
>>>>
>>>> $result = db_query("SELECT node.nid, node.title, node.type, node.uid FROM
>>>> node WHERE node.uid IN (SELECT node.uid FROM node
>>>> WHERE nid IN (SELECT nid FROM content_type_profile
>>>> WHERE field_city_value IN (SELECT field_city_value FROM content_type_profile
>>>> JOIN node ON content_type_profile.nid = node.nid
>>>> WHERE node.uid = 2 AND node.type = 'profile')))
>>>> AND node.uid != 2");
>>>> $member = db_fetch_object($result);
>>>> while($member = db_fetch_object($result)){
>>>> return $member->uid . "+";
>>>> }
>>>>
>>>> I expect it to come back "31+37+39+" but it's coming back only "37+" (if I
>>>> test in on a page and use "print" instead of "return", I get exactly what I
>>>> want)
>>>>
>>>> that would be my woeful php obviously for which I apologise now.
>>>>
>>>> I'm trying to adapt what Idan wrote but cannot get it to output multiple
>>>> UIDs to insert as the user:uid argument.
>>>>
>>>> I'm also getting Query Build Time in views of around 5050ms so I'm guessing
>>>> my sql is massively inefficient too...I do need the join and the nested
>>>> SELECTs though. I'm getting the UID of all the people who share the location
>>>> taxonomy term on their profile with the logged in user, so it was never
>>>> going to be easy!
>>>>
>>>> by the way, in my query, I'm hardcoding the logged in user's UID (2) just
>>>> for testing purposes.
>>>>
>>>> Neil
>>>>
>>>> On 20/11/2010 12:23, Idan Arbel wrote:
>>>>
>>>> You can see that I cycle through the id's and add them to $args[0] and
>>>> return it. Similar to what you did, try changing the variable name to
>>>> $args[0].
>>>>
>>>> for($i=1; $i<count($terms); $i++)
>>>> $args[0] = $args[0] ."+" .$terms[$i]; // replace the + with , if you want
>>>> and "And" action instead of "or"
>>>> }
>>>>
>>>> From: support-bounces at drupal.org [mailto:support-bounces at drupal.org] On
>>>> Behalf Of Neil Coghlan
>>>> Sent: Saturday, November 20, 2010 5:20 PM
>>>> To: support at drupal.org
>>>> Subject: Re: [support] Passing multiple values into a single Views argument
>>>>
>>>>
>>>>
>>>> hmm, can't see how that would apply in my case. Maybe it does, but can't see
>>>> it.
>>>>
>>>> bottom line: if an sql query returns 3 values, how do I get those 3 values
>>>> into a Views argument via "provide default argument"?
>>>>
>>>> On 20/11/2010 10:30, Idan Arbel wrote:
>>>>
>>>> Take a look at this code I used for something similar:
>>>>
>>>>
>>>>
>>>> if (arg(0) == 'node'&&    is_numeric(arg(1))) {
>>>> $node=node_load(arg(1));
>>>> $term = taxonomy_node_get_terms_by_vocabulary($node, 4); // 4 being the
>>>> vocabulary id
>>>> $terms = array_keys($term);
>>>> $args[0] = $terms[0];
>>>> for($i=1; $i<count($terms); $i++)
>>>> $args[0] = $args[0] ."+" .$terms[$i]; // replace the + with , if you want
>>>> and "And" action instead of "or"
>>>> }
>>>> return $args[0];
>>>>
>>>>
>>>>
>>>> might help you out.
>>>>
>>>> Idan
>>>>
>>>>
>>>>
>>>> From: support-bounces at drupal.org [mailto:support-bounces at drupal.org] On
>>>> Behalf Of Neil Coghlan
>>>> Sent: Saturday, November 20, 2010 3:25 PM
>>>> To: support at drupal.org
>>>> Subject: Re: [support] Passing multiple values into a single Views argument
>>>>
>>>>
>>>>
>>>> Idan, I only just realised myself there was an "accept multiple arguments"
>>>> checkbox....without that, I never would get it working!
>>>>
>>>> so...now with that checked, I still need to get the UID's passed in x,y,z or
>>>> x+y+z format.
>>>>
>>>> On 20/11/2010 10:21, Idan Arbel wrote:
>>>>
>>>> if you want to view to take them into account as using "AND" then return
>>>> them like so: 12+32+34, if you want it to take them into account as or
>>>> return them as so 12,32,34.
>>>>
>>>>
>>>>
>>>> don't forget to check to box in the argument settings area to accept
>>>> multiple arguments
>>>>
>>>> On Sat, Nov 20, 2010 at 3:14 PM, Neil Coghlan<neil at esl-lounge.com>    wrote:
>>>>
>>>> I have a view where I have selected User:uid as an argument and I am
>>>> using a sql query in the "Provide Default Argument" part. The problem
>>>> is, usually, the sql query is passing muliple UIDs back. How would I
>>>> pass all of them into the argument to be used by the view.
>>>>
>>>> At the moment, the view is only taking the first one.
>>>>
>>>> so, here is a simplified version of my php code:
>>>>
>>>> global $user;
>>>> $result = db_query("SELECT node.uid FROM {node}
>>>> WHERE node.type = 'profile'");
>>>> $member = db_fetch_object($result);
>>>> return "$member->uid";
>>>>
>>>> on my current db, this returns 3 UIDs...the view only takes the first one.
>>>>
>>>> Thanks
>>>>
>>>> Neil
>>>>
>>>>
>>>> --
>>>> [ Drupal support list | http://lists.drupal.org/ ]
>>>>
>>>>
>>>>
>>>> --
>>>> [ Drupal support list | http://lists.drupal.org/ ]
>>>>