[support] Retrieving View via Ajax

[Don]

I'm not sure how to retrieve just the block from the browser via ajax, 
but that's what I want. No tags, navigation, or anything else.
Normally if I'm outputting json I echo out the json, and then exit; so 
none of the rest gets sent. I'm just thinking that there's a better way.

-Don-


On 4/4/2011 5:16 PM, Marty Landman wrote:
> Am I missing something here? Why not output the view as a block? Then
> you can easily theme it prior to jquery switching it on for the
> desired page section - or should I say page region? :)
>
> Marty
>
> At 05:07 PM 4/4/2011, you wrote:
>> Hi,
>> I have a node whose main content area needs to be replaced by the output
>> of a View depending on the selection clicked on. This will be done with
>> a jquery call.
>> I configured the View as a page with a view right now, but I don't see
>> anything that would give me just the html of the View, not the
>> surrounding page html. An RSS feed doesn't seem to make sense, because I
>> couldn't format the html around the results.
>>
>> My thoughts are that I could retrieve the View results as html and just
>> create a new node within the container node right now, but I'm not quite
>> sure of how to get the stripped View results.
>>
>> Drupal 6.
>>
>> Any ideas to get me started?