You'll want to use http://example.com/admin/settings/featured-comments/feature/10840<http://example.com/admin/settings/featured-comments/feature?cid=10840> as url. But also: function feature_comment($cid = NULL) { if (!isset($cid)) { // Do something else. drupal_goto(...); } $comment = _comment_load($cid); db_query("UPDATE {featured_comments} SET featured=1 WHERE cid=%d", $cid); drupal_goto("node/$comment->nid"); } On Tue, Feb 3, 2009 at 11:34 AM, cooper Quintin <cooperq@cooperq.com> wrote:
Hello all, I am writing a module and I am trying to use a url as a callback argument, but it does not work. Here is the code:
$items[] = array( 'path' => 'admin/settings/featured-comments/feature', 'title' => t('featured comment'), 'callback' => 'feature_comment', 'callback_args' => $_GET['cid'], 'access' => user_access('administer comments'), 'type' => MENU_CALLBACK );
and the callback function: function feature_comment($cid) { $comment = _comment_load($cid); db_query("UPDATE {featured_comments} SET featured=1 WHERE cid=%d", $cid); drupal_goto("node/$comment->nid"); }
going to an example url: http://example.com/admin/settings/featured-comments/feature?cid=10840 gives the following error: warning: Missing argument 1 for feature_comment() in /var/www/html/sites/all/modules/featured_comments/featured_comments.module on line 149.
So my question is, what is the best way to use parts of the linked url as a callback argument for a function, because obviously it is not what I am doing! Thanks,
-- Cooper Quintin Freelance Programmer, Indymedia Journalist http://CooperQ.com (510) 827-5382