This is a real head scratcher.
I have two sites: mysite.com and it.mysite.com, the Italian version.
I noticed this morning a ton of mysql errors on pages where I have a block called "Related Pages". The sql query for this block is:
SELECT n.title, n.nid FROM {node} n INNER JOIN {term_node} tn ON n.nid = tn.nid WHERE tn.tid = $term->tid AND n.nid != $nid LIMIT 3
it gets me a list of 3 related pages that share the same taxonomy terms and was working perfectly about 4 days ago the last time I checked. Now it gives me the error:
user warning: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'DISTINCT(n.nid) FROM node n INNER JOIN term_node tn ON n.nid = tn.nid WHERE tn.t' at line 1 query: SELECT n.title, DISTINCT(n.nid) FROM node n INNER JOIN term_node tn ON n.nid = tn.nid WHERE tn.tid = 59 AND n.nid != 200 LIMIT 3 in /home/mysite/public_html/includes/database.mysql.inc on line 172.
I pasted the code into phpmyadmin and then noticed the difference between this and what I was getting on the Italian site which has identical code. For some reason, the DISTINCT was getting put into the code.
So in block config, the code has been pasted as:
SELECT n.title, n.nid FROM {node} n INNER JOIN {term_node} tn ON n.nid = tn.nid WHERE tn.tid = $term->tid AND n.nid != $nid LIMIT 3
and yet the query is being sent as:
SELECT n.title, DISTINCT(n.nid) FROM node n INNER JOIN term_node tn ON n.nid = tn.nid WHERE tn.tid = 59 AND n.nid != 200 LIMIT 3
and it is this which is causing an error. In phpmyadmin, when I take away the DISTINCT(), it works like a dream.
this is not happening on the Italian site despite identical block code. Now, I have been doing quite a bit of work with phpmyadmin in last few days although I can't think of anything I've changed on the english DB that may have created this result.
Do I have to start calling the mediums and reaching for the garlic and crucifix?
Neil