Re: [support] Testing for arg() OR is_front

Perhaps multiple calls to arg shifts..

How about this:

$a = arg(1); if(($a != 27) || ($a != 39) || !$is_front){ ?> <div>You won't see this on node/27, node/39 or the front page.</div> <?php }

On 12 July 2010 12:14, Hendry hendry.htc@gmail.com wrote:

I noticed that you have wrong syntax on this line: <?php if (arg(1) != "27") || (!$is_front): ?> It should be <?php if (arg(1) != "27" || !$is_front): ?>

# Hendry

On Mon, Jul 12, 2010 at 9:20 AM, Chris McCreery chris.mccreery@gmail.com wrote:

...

Right now I have this:

<?php if (arg(1) != '39'): ?>

<div> Content </div> <?php endif; ?> This works just fine but when i try to add in a second arg(1) and OR statement it doesn't work. Any ideas?

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