Drupal 6 site. I have a small image in a block in front of the header text , positioned using css. #myimage{ position:absolute; float:left; top:65px; left:50px; background:url("img/logo/myimage.png") no-repeat; height:170px; width:310px; }
It is referenced in page.tpl.php as <div id="myimage" > <?php print $myimage ?> </div> , it displays ok.
If I add <a href="go/to/another/url">This is my image</a> before the </div>, or before the <?print statement, It displays the link above the image. How can I display the link to the right side of the image instead of above? Is there a way of adding a class to do this? I would really appreciate help on this please. Thanks Roger