Hi Michel I am testing for this in my page.tpl.php trying to display a certain <div> when arg(1) doesn't equal 27 or 39.

On Sun, Jul 11, 2010 at 8:40 PM, Michel Morelli michel@ziobuddalabs.itwrote:

Chris McCreery ha scritto:

Hi I am trying to test for arg(1) OR is_front however when I set this up neither seem to work but if I do them separately they work fine. I assume it's just my syntax but I'm honestly not sure. Any help would be great.

Hi, where do you check this ? $is_front is available only in page(-*).tpl.php file, while $vars['is_front'] is available in themename_preprocess_page($vars) function.

M.

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I get node/10 so then arg(1) would be 10 correct? If I test for just arg(1) != "10" it works but when i try to combine multiple conditions doesn't work for me. I'm definitely not a php programmer so I'm sure it's a stupid error on my part.

Thanks,

On Sun, Jul 11, 2010 at 8:51 PM, Michel Morelli michel@ziobuddalabs.itwrote:

Chris McCreery ha scritto:

...

Hi Michel I am testing for this in my page.tpl.php trying to display a certain <div> when arg(1) doesn't equal 27 or 39.

Ok, for test at the top of page.tpl.php file write

echo $_GET['q'];

and see which is arg(1)

M.

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I noticed that you have wrong syntax on this line: <?php if (arg(1) != "27") || (!$is_front): ?> It should be <?php if (arg(1) != "27" || !$is_front): ?>

# Hendry

On Mon, Jul 12, 2010 at 9:20 AM, Chris McCreery chris.mccreery@gmail.com wrote:

Right now I have this:

<?php if (arg(1) != '39'): ?>

<div> Content </div> <?php endif; ?> This works just fine but when i try to add in a second arg(1) and OR statement it doesn't work. Any ideas?

A ha scritto:

Perhaps multiple calls to arg shifts..

How about this:

$a = arg(1); if(($a != 27) || ($a != 39) || !$is_front){ ?>

<div>You won't see this on node/27, node/39 or the front page.</div> <?php }

I think that you will see this div always :D For example: $_GET['q'] = 27 so arg(1) = 27 and $front is node/10

($a != 27) false OR ($a != 39) true OR (!$is_front) true so FALSE OR TRUE OR TRUE = TRUE

In any case a nid is always != 27 OR !39 or != 10.

Or am i wrong ?

M.

That was the problem. I need the ! statement at the beginning of both conditions. So in the end the following did the trick: <?php if (!(arg(1) == '39' || arg(1) == '49')): ?> <div> Content </div> <?php endif; ?>

Thank you so much for all your help everyone.

On Mon, Jul 12, 2010 at 8:17 AM, Earnie Boyd earnie@users.sourceforge.netwrote:

Chris McCreery wrote:

...

Right now I have this:

<?php if (arg(1) != '39'): ?>

<div> Content </div> <?php endif; ?>

This works just fine but when i try to add in a second arg(1) and OR statement it doesn't work. Any ideas?

I made this mistake often when I first started programming. Use AND and not OR when using !=. Or you could use the alternative method as show below.

<?php if (arg(1) != '39' && arg(1) != '49'): ?>

<div> Content </div> <?php endif; ?>

ALTERNATIVE:

<?php if (!(arg(1) == '39' || arg(1) == '49')): ?>

<div> Content </div> <?php endif; ?>

-- Earnie -- http://progw.com

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