support November 2007

support@drupal.org

80 participants
91 discussions

Automatically Add Users
by Robert C Corsaro 27 Nov '07

27 Nov '07

I'm using apache to do my authentication. If the user access any page, that means they are authenticated. Drupal never needs to worry about authenticating users. If the user doesn't exist, she should be added as a new user automatically. Is there a module or configuration that will automatically add users that access a page if they don't exist in Drupal already? Thanks Bob C

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Re: [support] CCK Common Fields
by Michelle Cox 27 Nov '07

27 Nov '07

I don't know any way to set it up to handle it automatically but, once you added the field to one content type, adding it to another is a lot simpler because you can re-use the field. Michelle On 11/27/2007 12:57:11 PM, Tom Holmes Jr. (tom(a)tomholmes.net) wrote: > I'm looking to implement Drupal 5.3 and I'm going to be using the CCK to > create some different content types. > > Two or more of my content types will have the same metadata field names > and types: > for example: date_created, date_modified, user_created, user_modified, > url > > Is there a way I can set this up so that my content types will ALWAYS > get these shared fields ... > or do I just have to setup those fields seperately with each content > type I create? > > Thanks! > Tom > > -- > [ Drupal support list | http://lists.drupal.org/ ]

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autosubscribe
by Liao, Kexiao 27 Nov '07

27 Nov '07

The drupal 5.3 supports setting all users to "autosubscribe" under Administer->Site configuration->Subscriptions when you login in as administrator. However it does not work in the current version. Is there any bug report related to this issue? Kevin P Please consider the environment before printing this e-mail Cleveland Clinic is ranked one of the top hospitals in America by U.S. News & World Report (2007). Visit us online at http://www.clevelandclinic.org for a complete listing of our services, staff and locations. Confidentiality Note: This message is intended for use only by the individual or entity to which it is addressed and may contain information that is privileged, confidential, and exempt from disclosure under applicable law. If the reader of this message is not the intended recipient or the employee or agent responsible for delivering the message to the intended recipient, you are hereby notified that any dissemination, distribution or copying of this communication is strictly prohibited. If you have received this communication in error, please contact the sender immediately and destroy the material in its entirety, whether electronic or hard copy. Thank you.

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How to import a node with file ?
by Davide Michel 'ZioBudda' Morelli 27 Nov '07

27 Nov '07

Hi all. I need to import (from an OLD proprietary CMS) more and more notes that have a file field. I have created my node type with a file CCK field, but I can not found how to create an entry for the file that was uploaded (like /tutorial/tutorialpsp3.zip). I use this method where $l contains the info of my OLD node: .... $node = array(); $node['type'] = "manuali_file"; /* NOT WORKS $l1 = split("/",$l[11]); $i2 = count($l1); $node['field_allegati_manuale_upload'] = array(0 => array( 'description' => $l1[($i2-1)], 'filename' => $l1[($i2-1)], 'filepath' => $l[11], 'filesize' => $l[10] ) ); */ //$node['field_allegati_manuale'] = $l[11]; $node['status'] = 0; $node['comment']=2; $node['promote'] = 0; $node['sticky'] = 0; $node['title']=$l[2]; $node['body']=$l[2]; $node['uid'] = 0; $node['status'] = 1; $d = split("/",$l[12]); $node['created']=mktime(0,0,0,$d[1],$d[0],$d[2]); $node['changed']=$node['created']; //Tiro fuori la id_categoria nuova $result = db_query("select tid from michel_import_old where id = ".$l[7]); $t = db_fetch_object($result); $node['taxonomy'] = array($t->tid); $node = node_submit($node); node_save($node); It works for normal node, But not for this one. Tnx. -- Michel 'ZioBudda' Morelli michel(a)ziobudda.net Consulenza sistemistica in ambito OpenSource. Sviluppo applicazioni web dinamiche (LAMP+Ajax) Telefono: 0200619074 Telefono Cell: +39-3939890025 -- Fax: +39-0291390660 http://www.ziobudda.net ICQ: 58351764 http://www.ziobuddalabs.it Skype: zio_budda http://www.ajaxblog.it MSN: michel(a)ziobuddalabs.it JABBER: michel(a)gmail.com

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Page-specific Block Content
by Fred Jones 27 Nov '07

27 Nov '07

I have a site where we want to show ads in a block. The content of the ads, however, is unique to each node. I am happy to put the content into a CCK field of the node, but I don't see a direct way to know the node being displayed. I can determine it programatically using arg(0) etc, and this seems like it will work, but I am wondering if there is an easier way. :) Some of the pages will also be Views, not just node pages. Thanks.

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Workflow access permissions
by Shyamala 27 Nov '07

27 Nov '07

Workflow access permissions does not get updated on change in workflow state for only two of my CCKs. For these two CCKs alone, I need to resubmit the Workflow access permissions to have it take effect for newly created nodes. i.e every time I create a node I need to go to Workflow access and submit. My Views show updated workflow state only after I resubmit! I am using ; Information added by drupal.org packaging script on 2007-04-26 version = "5.x-1.1" project = "workflow" Workflow is a very crucial component of the project. How to refresh the workflow access for these two CCKs alone. Use Drupal 5.3 OS: Windows Shyamala

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Some subforms module?
by Marolijo - Pol maresma 27 Nov '07

27 Nov '07

I looked but can't found some like this: (a 1 to many relation with an autocalculated total value) I need tot show a node with a list of attached lines with description and price, and a total sum of the prices. I know I can refer a node type to another but how I show this way? views can't do that really? thank's for all Pol Maresma / pol(a)polnetwork.com PolNetwork.com / Serveis d'Internet msn: marolijo

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images in trimmed node
by Roy Smith 26 Nov '07

26 Nov '07

I've got a node which consists of an image inside a float:right clear:right div, followed by a bunch of text. In the trimmed preview, only the image shows up. I can force both the image and the text to show up with "", but what I really want to do is get just the text. I can get just the text in the trimmed preview by moving it before the image, but that messes up the layout in the full view. Is there any way to tell the preview generator to just ignore images (or a specific div)? -- roy(a)panix.com

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Validation function name when using hook_forms()
by Steve Edwards 26 Nov '07

26 Nov '07

I'm trying to use hook_forms() to use one form builder function to generate multiple forms. In the process of writing a very long e-mail, I got most of it figured out, but that leads to other questions. :-) My module will create multiple forms on one page, one for each project listed in the project_projects table. Here is the code I have so far: <?php //$Id$ /* * Adds the capability to assign access to projects * to specific users */ /* * Implementation of hook_menu() */ function project_permissions_menu($may_cache) { $items = array(); if ($may_cache) { $items[] = array( 'path' => 'admin/project/project_permissions', 'title' => t('Project Permissions'), 'description' => t('Set access to projects'), 'access' => user_access('administer projects'), 'callback' => 'project_permissions_page', 'type' => MENU_NORMAL_ITEM ); } return $items; } function project_permissions_page() { $output = t('Use this page to assign permissions to each project'); //get list of projects $sql = "SELECT nid, uri FROM {project_projects}"; $result = db_query($sql); //for each project, create a fieldset with project and user fields while ($projects = mysql_fetch_object($result)) { $project_name = $projects->uri; $project_nid = $projects->nid; //call form function $output .= drupal_get_form($project_name.'_permissions_form'); } return $output; } /* * Implementation of hook_forms() */ function project_permissions_forms() { $sql = "SELECT nid, uri FROM project_projects"; $result = db_query($sql); while ($project = mysql_fetch_object($result)) { $forms[$project->uri.'_permissions_form'] = array( 'callback' => 'project_permissions_form', 'callback arguments' => array($project->nid, $project->uri) ); } return $forms; } /* * Define the project permissions settings form */ function project_permissions_form($project_nid, $project_name) { $form[$project_nid] = array( '#type' => 'fieldset', '#title' => $project_name, '#collapsible' => TRUE, '#collapsed' => FALSE, ); $form[$project_nid]['projects'] = array( '#type' => 'textfield', '#title' => t('Project name'), '#maxlength' => 30, '#size' => 30, '#default_value' => $project_name, ); $form[$project_nid]['users'] = array( '#type' => 'select', '#title' => t('Users with access to project'), '#description' => t('Select users to be asssigned to the project'), '#options' => _get_user_list(), '#multiple' => TRUE ); $form[$project_nid]['nid'] = array( '#type' => 'hidden', '#value'=> $project_nid, ); $form[$project_nid]['submit'] = array( '#type' => 'submit', '#value' => 'Submit' ); return $form; } /* * Gets lists of projects from project_projects table */ function _get_projects_list() { $sql = "SELECT nid, uri FROM {project_projects}"; $result = db_query($sql) or die('Error'. mysql_error()); while($projects = db_fetch_object($result)) { $options[$projects->nid] = $projects->uri; } return $options; } /* * Gets lists of users from users table */ function _get_user_list() { $sql = "SELECT uid, name FROM {users} WHERE uid > %d"; $result = db_query($sql,0) or die('Error'. mysql_error()); while($users = db_fetch_object($result)) { $options[$users->uid] = $users->name; } return $options; } This gets me what I want: one form for each project in a collapsible fieldset. Now that I have a separate form for each, what do I name my validation function? Is it the name of my form builder function plus '_submit'? That seems logical, but it isn't working. If I name my submit function with the name of a specific project (i.e. XYZ_permissions_form_submit() for project XYZ), it works like a charm, but if I just use project_permissions_form_submit(), it doesn't do anything. Thanks. Steve

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Directory issue
by A-NO-NE Music 25 Nov '07

25 Nov '07

Because of the inconveniences when updating Drupal core, I have Drupal files under a subdirectory: ~/public_html/drupal/ This way, I can dup the directory to update the core and test drive before the switchover. However, I still need the drupal directory to be the root to the public, so I put this in .htaccess: RewriteRule (.*) drupal/$1 [L] This works great. Public audience doesn't see /drupal/ subdirectory. However, this killed all of my sub-domains such as private.mydomain.com. I guess I can copy all the sub-domains' subdirectories under drupal directory but I do not wish to do so for obvious reasons. Any help would be appreciated. -- - Hiro Hiroaki Honshuku, A-NO-NE Music, Boston, MA <http://a-no-ne.com> <http://anonemusic.com>

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support November 2007